Summary:

Suppose we have an array of n integers. Through the below C++ code, we will check whether the array contains a triplet that sums up to zero. 

Solution:

Explenation:

• Initially, the input array arr is sorted in ascending order using sort(arr, arr+n).

• Then, a for loop is used to iterate through the array from the beginning to the second-to-last element (n-2).

Two pointers, l (left) and r (right), are initialized within the loop.

• l starts one element after the current element i.

• r starts at the last element of the array.

A while loop is employed to iterate until the left pointer (l) is less than the right pointer (r).

Calculating Sum:

The sum of the current triplet (arr[i] + arr[l] + arr[r]) is calculated.

• If the sum becomes zero at any point, the function returns 1 (true), indicating the presence of a triplet with a zero sum.

• If the loop completes without finding such a triplet, the function returns 0 (false).

Answered by: >surajkumaae3j

Credit: >GeekforGeeks

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